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Algebra / Systems of two linear equations in two variables Difficulty: Hard

78y-58x=47-78y

54x+74=py+154


In the given system of equations, p is a constant. If the system has no solution, what is the value of p ?

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Explanation

The correct answer is 72. A system of two linear equations in two variables, x and y , has no solution if the lines represented by the equations in the xy-plane are distinct and parallel. Two lines represented by equations in standard form Ax+By=C, where A , B , and C are constants, are parallel if the coefficients for x and y in one equation are proportional to the corresponding coefficients in the other equation. The first equation in the given system, 78y-58x=47-78y, can be written in standard form by adding 78y to both sides of the equation, which yields 148y-58x=47, or -58x+148y=47. Multiplying each term in this equation by -8 yields 5x-14y=-327. The second equation in the given system, 54x+74=py+154, can be written in standard form by subtracting 74 and py from both sides of the equation, which yields 54x-py=84. Multiplying each term in this equation by 4 yields 5x-4py=8. The coefficient of x in the first equation, 5x-14y=-327, is equal to the coefficient of x in the second equation, 5x-4py=8. For the lines to be parallel, and for the coefficients for x and y in one equation to be proportional to the corresponding coefficients in the other equation, the coefficient of y in the second equation must also be equal to the coefficient of y in the first equation. Therefore, -14=-4p. Dividing both sides of this equation by -4 yields -14-4=p, or p=72. Therefore, if the given system of equations has no solution, the value of p is 72. Note that 7/2 and 3.5 are examples of ways to enter a correct answer.